WBJEE · Maths · Probability
A fair coin is tossed at a fixed number of times. If the probability of getting exactly 3 heads equals the probability of getting exactly 5 heads, then the probability of getting exactly one head is
- A \(1 / 64\)
- B \(1 / 32\)
- C \(1 / 16\)
- D \(1 / 8\)
Answer & Solution
Correct Answer
(B) \(1 / 32\)
Step-by-step Solution
Detailed explanation
Let the coin be tossed \(n\) times Let getting head is consider to be success \(\therefore \quad p=\frac{1}{2}, q=1-p=1-\frac{1}{2}=\frac{1}{2}\) It is given that, \(P(X=3)=P(X=5)\)…
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