WBJEE · Chemistry · Structure of Atom
Two base balls (masses: \(m_1=100 \mathrm{~g}\), and \(m_2=50 \mathrm{~g}\) ) are thrown. Both of them move with uniform velocity, but the velocity of \(m_2\) is 1.5 times that of \(m_1\). The ratio of de Broglie wavelengths \(\lambda\left(m_1\right): \lambda\left(m_2\right)\) is given by
- A \(4: 3\)
- B \(3: 4\)
- C \(2: 1\)
- D \(1: 2\)
Answer & Solution
Correct Answer
(B) \(3: 4\)
Step-by-step Solution
Detailed explanation
Hint : \(\frac{\lambda_1}{\lambda_2}=\frac{m_2 \mathrm{~V}_2}{m_1 \mathrm{~V}_1}=\frac{50 \times 1.5 \mathrm{~V}_1}{100 \times \mathrm{V}_1}=\frac{1.5}{2}=\frac{3}{4}\)
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