WBJEE · Chemistry · Solid State
Suppose the mass of a single Ag-atom is \(m\). Ag metal crystallises in fcc lattice with unit cell of length \(a\). The density of Ag metal in terms of \(a\) and \(m\) is
- A \(\frac{4 m}{a^{3}}\)
- B \(\frac{2 m}{a^{3}}\)
- C \(\frac{m}{a^{3}}\)
- D \(\frac{m}{4 a^{3}}\)
Answer & Solution
Correct Answer
(A) \(\frac{4 m}{a^{3}}\)
Step-by-step Solution
Detailed explanation
Given that, Mass of single Ag-atom \(=m\) Unit cell length \(=a\) Total atoms present per unit cell of fcc lattice \(=4\) Therefore, mass of unit cell becomes \(4 \mathrm{m}\). Volume of unit cell \(=a^{3}\) Density…
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