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WBJEE · Chemistry · p Block Elements (Group 15, 16, 17 & 18)

\(\mathrm{PbCl}_{2}\) is insoluble in cold water. Addition of \(\mathrm{HCl}\) increases its solubility due to

  1. A formation of soluble complex anions like \(\left[\mathrm{PbCl}_{3}\right]^{-}\)
  2. B oxidation of Pb(II) to PB(iV)
  3. C formation of \(\left[\mathrm{Pb}(\mathrm{H}_{2}\mathrm{O})_{6}\right]^{2}\)
  4. D formation of polymeric lead complexes
Verified Solution

Answer & Solution

Correct Answer

(A) formation of soluble complex anions like \(\left[\mathrm{PbCl}_{3}\right]^{-}\)

Step-by-step Solution

Detailed explanation

\(\mathrm{PbCl}_{2}\) react with HCl as follows \(\mathrm{PbCl}_{2}(s)+\mathrm{Cl}^{-} \stackrel{\text { Cold }}{\longrightarrow}\left[\mathrm{PbCl}_{3}\right]^{-}(a q)\)…