WBJEE · Chemistry · Ionic Equilibrium
Dissolving NaCN in de-ionised water will result in a solution having
- A \(\mathrm{pH} < 7\)
- B \(\mathrm{pH}=7\)
- C \(\mathrm{pOH}=7\)
- D \(\mathrm{pH}>7\)
Answer & Solution
Correct Answer
(D) \(\mathrm{pH}>7\)
Step-by-step Solution
Detailed explanation
\(\because\) On dissolving NaCN in de-ionised water, following reaction takes place. \(\mathrm{CN}^{-}+\mathrm{H}_{2} \mathrm{O} \rightleftharpoons \mathrm{HCN}+\mathrm{OH}^{-}\) CN- ions come from the salt of strong base and weak acid. \(\therefore\) The solution becomes basic…
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