WBJEE · Chemistry · Chemical Bonding and Molecular Structure
CO is practically non-polar since
- A the \(\sigma\) -electron drift from \(C\) to \(O\) is almost nullified by the \(\pi\) -electron drift from \(\mathrm{O}\) to \(\mathrm{C}\)
- B the \(\sigma\)-clectron drift from O to C is almost nullified by the \(\pi\) -electron drift from \(\mathrm{C}\) to \(\mathrm{O}\)
- C the bond moment is low
- D there is a triple bond berween \(\mathrm{C}\) and \(\mathrm{O}\)
Answer & Solution
Correct Answer
(A) the \(\sigma\) -electron drift from \(C\) to \(O\) is almost nullified by the \(\pi\) -electron drift from \(\mathrm{O}\) to \(\mathrm{C}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{C} \frac{\pi}{\sigma} \mathrm{O}\) In \(\mathrm{CO}\) molecule, \(\mathrm{C}-\mathrm{O} \sigma\) moment and \(\mathrm{O}-\mathrm{C}\) \(\pi\) -moment cancels each other. So that it is non-polar.
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