WBJEE · Chemistry · Chemical Kinetics
\({ }_{98} \mathrm{Cf}^{246}\) was formed along with a neutron when an unknown radioactive substance was bombarded with \({ }_{6} \mathrm{C}^{12}\). The unknown substance was :
- A \({ }_{91} \mathrm{~Pa}^{234}\)
- B \({ }_{90} \mathrm{Th}^{234}\)
- C \({ }_{92} \mathrm{U}^{235}\)
- D \({ }_{92} \mathrm{U}^{238}\)
Answer & Solution
Correct Answer
(C) \({ }_{92} \mathrm{U}^{235}\)
Step-by-step Solution
Detailed explanation
Let, the unknown radioactive substance be \({ }_{x} A^{y}\). \(x A^{y}+{ }_{6} C^{12} \longrightarrow{ }_{98} C f^{246}+{ }_{0} n^{1}\) On comparing atomic numbers, we get \[ \begin{array}{r} x+6=98+0 \\ x=98-6=92 \end{array} \] On comparing mass numbers, we get \[ y+12=246+1 \]…
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