TS EAMCET · Physics · Electromagnetic Induction

Two long wires with no contact are placed perpendicular to each other. $i,$ and $i_{2},$ are currents flowing through these wires respectively. The magnetic force on a small length $' d'$ of the second wire situated at a distance $' l'$ from, the first wire is proportional to,

A $i_{1} i_{2}$
B $l$
C $\frac{1}{i_{1} i_{2}}$
D $l^{2}$

Verified Solution

Answer & Solution

Correct Answer

(A) $i_{1} i_{2}$

Step-by-step Solution

Detailed explanation

The formula of magnetic force, in terms of current and length of the wire is, F=iBlsinθ, then the formula of the magnetic field due to infinite wire is, B=μ02π×i1r, then the force due to current-carrying wire,…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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Two long wires with no contact are placed perpendicular to each other. i, and i2, are currents flowing through these wires respectively. The magnetic force on a small length 'd' of the second wire situated at a distance 'l' from, the first wire is proportional to,

Step-by-step Solution

Two long wires with no contact are placed perpendicular to each other. $i,$ and $i_{2},$ are currents flowing through these wires respectively. The magnetic force on a small length $' d'$ of the second wire situated at a distance $' l'$ from, the first wire is proportional to,