TS EAMCET · Physics · Mechanical Properties of Fluids
The work done in increasing the diameter of a soap bubble from 2 cm to 4 cm is (Surface tension of soap solution \(=3.5 \times 10^{-2} \mathrm{Nm}^{-1}\) )
- A \(528 \times 10^{-6} \mathrm{~J}\)
- B \(132 \times 10^{-6} \mathrm{~J}\)
- C \(264 \times 10^{-6} \mathrm{~J}\)
- D \(178 \times 10^{-6} \mathrm{~J}\)
Answer & Solution
Correct Answer
(C) \(264 \times 10^{-6} \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
In case of soap bubble work done in increasing area…
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