TS EAMCET · Physics · Thermal Properties of Matter
The temperature at which the reading on Fahrenheit scale becomes \(90 \%\) more than the reading on Celsius scale is
- A \(280^{\circ} \mathrm{F}\)
- B \(580^{\circ} \mathrm{F}\)
- C \(608^{\circ} \mathrm{F}\)
- D \(320^{\circ} \mathrm{F}\)
Answer & Solution
Correct Answer
(C) \(608^{\circ} \mathrm{F}\)
Step-by-step Solution
Detailed explanation
\(F = 1.9C\) \(1.9C = \frac{9}{5}C + 32\) \(0.1C = 32 \Rightarrow C = 320^{\circ} \mathrm{C}\) \(F = 1.9 \times 320 = 608^{\circ} \mathrm{F}\)
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