TS EAMCET · Physics · Waves and Sound
The speed of a transverse wave in a stretched string ' \(A\) ' is ' \(v\) '. Another string ' \(B\) ' of same length and same radius is subjected to same tension. If the density of the material of the string ' \(B\) ' is \(2 \%\) more than that of ' \(A\) ', then the speed of the transverse wave in string ' \(B\) ' is
- A \(\sqrt{1.04} v\)
- B \(\sqrt{1.02} v\)
- C \(\frac{v}{\sqrt{1.04}}\)
- D \(\frac{v}{\sqrt{1.02}}\)
Answer & Solution
Correct Answer
(D) \(\frac{v}{\sqrt{1.02}}\)
Step-by-step Solution
Detailed explanation
Frequency \(n=\frac{V}{\lambda}=\sqrt{\frac{T}{\pi r^2 d}}\) where \(d=\) density \(\therefore \mathrm{V}=\lambda \sqrt{\frac{\mathrm{T}}{\pi \mathrm{r}^2 \mathrm{~d}}} \text { so here } \mathrm{V} \propto \frac{1}{\sqrt{\mathrm{~d}}}\) If the density of the material of the…
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