TS EAMCET · Physics · Motion In Two Dimensions
Consider an object making uniform motion around a circle of radius \(5 \mathrm{~m}\) with tangential velocity \(2 \mathrm{~ms}^{-1}\). The time it takes to complete 2 revolution and the magnitude of acceleration respectively are
- A \(0.2 \pi \mathrm{s}\) and \(0.8 \mathrm{~ms}^{-2}\)
- B \(0.5 \pi \mathrm{s}\) and \(1 \mathrm{~ms}^{-2}\)
- C \(10 \pi \mathrm{s}\) and \(0.8 \mathrm{~ms}^{-2}\)
- D \(5 \pi \mathrm{s}\) and \(5 \mathrm{~ms}^{-2}\)
Answer & Solution
Correct Answer
(C) \(10 \pi \mathrm{s}\) and \(0.8 \mathrm{~ms}^{-2}\)
Step-by-step Solution
Detailed explanation
Given that, circle of radius \(=5 \mathrm{~m}\) tangential velocity \(=2 \mathrm{~m} / \mathrm{s}\) \( \text { Here, } 2 \text { revolutions complete by object. } \) \(\because\) We know that,…
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