TS EAMCET · Physics · Work Power Energy
A metal chain of mass \(2 \mathrm{~kg}\) and length \(90 \mathrm{~cm}\) over hangs a table with \(60 \mathrm{~cm}\) on the table. How much work needs to be done to put the hanging part of the chain back on the table? \(\left(\right.\) Let \(\left.g=10 \mathrm{~m} / \mathrm{s}^2\right)\)
- A \(2 \mathrm{~J}\)
- B \(10 \mathrm{~J}\)
- C \(1 \mathrm{~J}\)
- D \(3 \mathrm{~J}\)
Answer & Solution
Correct Answer
(C) \(1 \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
Given, mass of metal chain, \(m=2 \mathrm{~kg}\), Total length of chain, \(l=90 \mathrm{~cm}=0.9 \mathrm{~m}\), Hanging length of chain, \(l^{\prime}=(90-60) \mathrm{cm}\) \(=30 \mathrm{~cm}=0.3 \mathrm{~m}\) The distance of centre of gravity of hanging length from the table,…
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