TS EAMCET · Physics · Current Electricity
A conductor of length \(100 \mathrm{~cm}\) and area of cross-section \(1 \mathrm{~mm}^2\) carries a current of \(5 \mathrm{~A}\). If the resistivity of the material of the conductor is \(3.0 \times 10^{-8} \Omega-\mathrm{m}\), then the electric field across the conductor is
- A 0.15 V/m
- B \(0.015 \mathrm{~V} / \mathrm{m}\)
- C \(1.5 \mathrm{~V} / \mathrm{m}\)
- D \(0.0015 \mathrm{~V} / \mathrm{m}\)
Answer & Solution
Correct Answer
(A) 0.15 V/m
Step-by-step Solution
Detailed explanation
Current density is related to electric field as \(\mathbf{J}=\frac{\mathbf{E}}{\rho}\) where, \(\rho=\) resistivity. Here, \(I=5 \mathrm{~A}, A=1 \mathrm{~mm}^2=1 \times 10^{-6} \mathrm{~m}^2\) and \(\rho=3 \times 10^{-8} \Omega-\mathrm{m}\) So, electric field inside the…
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