TS EAMCET · Maths · Limits
\(\lim _{x \rightarrow 0} \frac{1-\cos \left(x^2+\pi(x+2)\right)}{x^2}=\)
- A \(\frac{\pi}{2}\)
- B \(\frac{\pi^2}{4}\)
- C \(\frac{\pi^2}{2}\)
- D \(\frac{\pi}{4}\)
Answer & Solution
Correct Answer
(C) \(\frac{\pi^2}{2}\)
Step-by-step Solution
Detailed explanation
We have, \(\lim _{x \rightarrow 0} \frac{1-\cos \left(x^2+\pi(x+2)\right.}{x^2}\) \(\lim _{x \rightarrow 0} \frac{1-\cos \left(2 \pi+\pi x+x^2\right)}{x^2}\) \(\lim _{x \rightarrow 0} \frac{1-\cos \left(\pi x+x^2\right)}{x^2} \quad[\because \cos (2 \pi+\theta)=\cos \theta]\)…
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