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TS EAMCET · Maths · Limits

\(\lim _{x \rightarrow 0} \frac{1-\cos \left(x^2+\pi(x+2)\right)}{x^2}=\)

  1. A \(\frac{\pi}{2}\)
  2. B \(\frac{\pi^2}{4}\)
  3. C \(\frac{\pi^2}{2}\)
  4. D \(\frac{\pi}{4}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{\pi^2}{2}\)

Step-by-step Solution

Detailed explanation

We have, \(\lim _{x \rightarrow 0} \frac{1-\cos \left(x^2+\pi(x+2)\right.}{x^2}\) \(\lim _{x \rightarrow 0} \frac{1-\cos \left(2 \pi+\pi x+x^2\right)}{x^2}\) \(\lim _{x \rightarrow 0} \frac{1-\cos \left(\pi x+x^2\right)}{x^2} \quad[\because \cos (2 \pi+\theta)=\cos \theta]\)…