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TS EAMCET · Maths · Properties of Triangles

In \(\triangle A B C\), the points \(P, Q, R\) divide \(B C, C A, A B\) in the ratio \(3: 4,2: 5,9: 5\), respectively and the point \(D\) divides \(B C\) in the ratio \(2: 3\). If \(\mathbf{A P}+\mathbf{B Q}+\mathbf{C R}=k \mathbf{A D}\), then \((14 k+1):(14 k-1)=\)

  1. A \(7: 5\)
  2. B \(4: 3\)
  3. C \(4: 5\)
  4. D \(3: 2\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(3: 2\)

Step-by-step Solution

Detailed explanation

Here, \(\mathbf{P}=\frac{3 \mathbf{c}+4 \mathbf{b}}{7}, \mathbf{Q}=\frac{5 \mathbf{c}}{7}\) and \(\mathbf{R}=\frac{9 \mathbf{b}}{14}\) Now, \(\mathbf{A P}+\mathbf{B Q}+\mathbf{C R}\)…
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