TS EAMCET · Maths · Straight Lines
The vertices of a triangle are \(A(1,7), B(-5,-1)\) and \(C(-1,2)\). Then, the equation of a bisector of the \(\angle A B C\) is
- A \(x-y+4=0\)
- B \(x+y+4=0\)
- C \(2 x-3 y+6=0\)
- D \(x-2 y+4=0\)
Answer & Solution
Correct Answer
(A) \(x-y+4=0\)
Step-by-step Solution
Detailed explanation
We have, vertices of triangle are \(A(1,7), B(-5,1)\) and \(C(-1,4)\) Equation of line \(A B\) is \( \begin{aligned} & y+1=\frac{7+1}{1+5}(x+5) \Rightarrow y+1=\frac{4}{3}(x+5) \\ & \Rightarrow \quad 4 x-3 y+17=0 \\ & \end{aligned} \) Equation of line \(B C\) is…
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