TS EAMCET · Maths · Three Dimensional Geometry
The sum of the squares of the perpendicular distances of a point \((\mathrm{x}, \mathrm{y}, \mathrm{z})\) from the coordinate axes is \(\mathrm{k}\) times the square of the distance of the point from the origin. Then \(\mathrm{k}=\)
- A \(2\)
- B \(3\)
- C \(1\)
- D \(4\)
Answer & Solution
Correct Answer
(A) \(2\)
Step-by-step Solution
Detailed explanation
Distance of \((x, y, z)\) (a) From \(x\) axis i.e. \((x, 0,0)\) \(d=\sqrt{y^2+z^2}\) (b) From \(y\) axis i.e. \((0, y, 0)\) \(d_2=\sqrt{x^2+z^2}\) (c) From \(z\) axis i.e. \((0,0, z)\) \(d_3=\sqrt{x^2+y^2}\) Distance of \((x, y, z)\) from origin \(d=\sqrt{x^2+y^2+z^2}\)…
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