TS EAMCET · Maths · Ellipse
The sum of the focal distances of the point \(\left(\frac{4}{\sqrt{5}}, \frac{3}{\sqrt{5}}\right)\) on the ellipse \(9 x^2+4 y^2=36\) is
- A 12
- B 4
- C 9
- D 6
Answer & Solution
Correct Answer
(D) 6
Step-by-step Solution
Detailed explanation
Given, Equation of ellipse is \( 9 x^2+4 y^2=36 \) \(\Rightarrow \quad \frac{x^2}{4}+\frac{y^2}{9}=1\) Here, \(\quad a=2\) and \(b=3\) \(P F_1+P F_2=\) sum of focal distances of \(P\). \(\begin{aligned} & =2 b \\ & =2 \times 3=6\end{aligned}\)
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