TS EAMCET · Maths · Continuity and Differentiability
Suppose \(f: R \rightarrow R\) defined as \(f(x)=\left\{\begin{array}{ll}{[\cos \pi x],} & x \leq 1 \ 2\{x\}-1, & x>1\end{array}\right.\), where \([\cdot]\) and \(\{\cdot\}\) denote the greatest integer function and the fractional part of \(x\) respectively, then at \(x=1\)
- A right derivatives is 2
- B left derivatives is 2
- C right derivative is 0
- D left derivative is −1
Answer & Solution
Correct Answer
(A) right derivatives is 2
Step-by-step Solution
Detailed explanation
\(f(x)= \begin{cases}{[\cos \pi x],} & x \leq 1 \\ 2\{x\}-1, & x>1\end{cases}\) From the given option we observe that, when \(x>1\), then \(f(x)=2(x-1)-1=2 x-3\) and \(f^{\prime}(x)=2, x>1\) So, RHL at \(x=1\) is \(f^{\prime}(\mathrm{l})=2\)
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