TS EAMCET · Maths · Binomial Theorem
The sum of the coefficients of \(x^{-3 / 2}\) and \(x^3\) in the expansion of \(\sqrt{3+x}+\sqrt{5+x}\) when \(3 < x < 5\), is
- A \(\frac{-9+\sqrt{5}}{16}\)
- B \(\frac{3 \times 5^{-5 / 2}-18}{8}\)
- C \(\frac{-6+\sqrt{5}}{6}\)
- D \(\frac{5-\sqrt{6}}{6}\)
Answer & Solution
Correct Answer
(B) \(\frac{3 \times 5^{-5 / 2}-18}{8}\)
Step-by-step Solution
Detailed explanation
We have, \(\sqrt{3+x}+\sqrt{5+x}\)…
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