TS EAMCET · Maths · Straight Lines
The straight line \(x+y+1=0\) bisects an angle between the pair of lines of which one is \(2 x+3 y-4=0\). Then, the equation of the other line is
- A \(3 x-2 y+9=0\)
- B \(3 x-2 y-9=0\)
- C \(3 x+2 y+9=0\)
- D \(x-y-1=0\)
Answer & Solution
Correct Answer
(C) \(3 x+2 y+9=0\)
Step-by-step Solution
Detailed explanation
Let slope of required line \(=m\) The angle between bisector and new line will be same as between bisector \(x+y+1\) and line \(2 x+3 y-4=0\) \(\therefore\) Angle between bisector \(x+y+1=0\) and new line is \[ \tan \theta=\left|\frac{m+1}{1-m}\right| \]…
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