TS EAMCET · Maths · Probability
If \(A\) and \(B\) are two events such that \(P(A / B)=0.6, P(B / A)=0.3\) and \(P(A)=0.1\), then \(P(\bar{A} \cap \bar{B})\) equals
- A 0.88
- B 0.12
- C 0.6
- D 0.4
Answer & Solution
Correct Answer
(A) 0.88
Step-by-step Solution
Detailed explanation
We have, \[ P(A / B)=0.6, P(B / A)=0.3, P(A)=0.1 \] We know that, \[ \begin{array}{rlrl} P(B / A) & =\frac{P(B \cap A)}{P(A)} \\ \Rightarrow & & 0.3 & =\frac{P(B \cap A)}{0.1} \\ \Rightarrow & P(B \cap A) & =0.03 \\ \text { or } & P(A \cap B) & =0.03 \end{array} \] Also,…
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