TS EAMCET · Maths · Three Dimensional Geometry
The shortest distance between the lines \(\mathbf{r}=(3 t-4) \hat{\mathbf{i}}-2 \hat{\mathbf{j}}-(1+2 t) \hat{\mathbf{k}}\) and \(\mathbf{r}=(6+s) \hat{\mathbf{i}}+(2-2 s) \hat{\mathbf{j}}+2(\mathfrak{l}+s) \hat{\mathbf{k}}\) is
- A 3
- B 6
- C 9
- D 12
Answer & Solution
Correct Answer
(C) 9
Step-by-step Solution
Detailed explanation
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