TS EAMCET · Maths · Application of Derivatives
The radius of a circular plate is increasing at the rate of \(0.01 \mathrm{~cm} / \mathrm{s}\) when the radius is \(12 \mathrm{~cm}\). Then, the rate at which the area increases, is
- A \(0.24 \pi \mathrm{sq} \mathrm{cm} / \mathrm{s}\)
- B \(60 \pi \mathrm{sq} \mathrm{cm} / \mathrm{s}\)
- C \(24 \pi \mathrm{sq} \mathrm{cm} / \mathrm{s}\)
- D \(1.2 \pi \mathrm{sq} \mathrm{cm} / \mathrm{s}\)
Answer & Solution
Correct Answer
(A) \(0.24 \pi \mathrm{sq} \mathrm{cm} / \mathrm{s}\)
Step-by-step Solution
Detailed explanation
The area of circular plate is \(A=\pi r^2\) On differentiating w.r.t. \(t\), we get…
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