ExamBro
ExamBro
TS EAMCET · Maths · Probability

The probability distribution of a random variable X is given below.
X=x 0 1 2 3 4 5 6 7
P(x) 0.01 0.10 0.26 0.33 0.18 0.06 K 0.04
Then P(X3)-P(X<6)=

  1. A 0.24
  2. B -0.27
  3. C 0.57
  4. D -0.31
Verified Solution

Answer & Solution

Correct Answer

(D) -0.31

Step-by-step Solution

Detailed explanation

Since, ∑x=07Px=1 ⇒0.01+0.10+0.26+0.33+0.18+0.06+K+0.04=1 ⇒K=1-0.98=0.02 Now, Px≥3-Px<6 =0.33+0.18+0.06+0.02+0.04-0.01+0.1+0.26+0.36+0.18+0.66=-0.31