TS EAMCET · Maths · Three Dimensional Geometry
The point of intersection of the line passing through the points \(\hat{i}-\hat{j}, \hat{j}-\hat{k}\) and the plane passing through the points \(2 \hat{i}+\hat{j}, 2 \hat{j}-\hat{k}, \hat{i}+2 \hat{k}\) is
- A \(-(-5 \hat{i}+16 \hat{j}-11 \hat{k})\)
- B \(\frac{1}{23}(22 \hat{i}-44 \hat{j}+25 \hat{k})\)
- C \(\frac{1}{5}(18 \hat{i}+16 \hat{j}-21 \hat{k})\)
- D \(\frac{1}{11}(5 \hat{i}-41 \hat{j}+21 \hat{k})\)
Answer & Solution
Correct Answer
(A) \(-(-5 \hat{i}+16 \hat{j}-11 \hat{k})\)
Step-by-step Solution
Detailed explanation
Equation of line passing through \(\vec{a}\) and \(\vec{b}\) is \(\begin{aligned} & \vec{r}=\vec{a}+\lambda(\vec{b}-\vec{a}) \\ & \vec{r}=(\hat{i}-\hat{j})+\lambda(-\hat{i}+2 \hat{j}-\hat{k})\end{aligned}\) \(\vec{r}=(1-\lambda) \hat{i}+(2 \lambda-1) \hat{j}-\lambda \hat{k}\)…
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