TS EAMCET · Maths · Three Dimensional Geometry
The perimeter of the triangle with vertices at \((1,0,0),(0,1,0)\) and \((0,0,1)\) is
- A 3
- B 2
- C \(2 \sqrt{2}\)
- D \(3 \sqrt{2}\)
Answer & Solution
Correct Answer
(D) \(3 \sqrt{2}\)
Step-by-step Solution
Detailed explanation
Let \(A=(1,0,0), B=(0,1,0)\) and \(C=(0,0,1)\) Now, \(\begin{aligned} \text { Now, } A B & =\sqrt{(0-1)^2+(1-0)^2+0^2}=\sqrt{2} \\ B C & =\sqrt{0^2+(0-1)^2+(1-0)^2}=\sqrt{2} \\ \text { and } \quad C A & =\sqrt{(1-0)^2+0^2+(0-1)^2}=\sqrt{2} \end{aligned}\)…
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