TS EAMCET · Maths · Permutation Combination
The number of ways in which \(\mathrm{n}\) boys and \(\mathrm{n}\) girls can be arranged in a row such that all the boys are together and all the girls are also together is equal to
- A the number of ways in which \(n\) boys and \(n\) girls can be arranged in a row
- B the number of ways in which \(\mathrm{n}\) boys and \(\mathrm{n}\) girls can be arranged in a row such that all the girls are together
- C the number of ways in which \(\mathrm{n}\) boys and \(\mathrm{n}\) girls can be arranged in a row such that no two girls are together
- D none of these
Answer & Solution
Correct Answer
(D) none of these
Step-by-step Solution
Detailed explanation
Making 2 groups of \(n\) girls and \(n\) boys and arrange them \(=n ! \cdot n ! \times 2 !\) Now number of ways to arrange \(n\) boys and \(n\) girls no two girl or boy are together. Arrange \(n\) boys alternately in \(n\) ! ways there will be \((n+1)\) gaps, select \(n\) gaps…
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