TS EAMCET · Maths · Three Dimensional Geometry

$A (2, 3, - 4), B (- 3, 3, - 2), C (- 1, 4, 2)$ and $D (3, 5, 1)$ are the vertices of a tetrahedron. If $E, F, G$ are the centroids of its faces containing the point $A,$ then the centroid of the triangle $E F G$ is

A $(\frac{1}{9}, \frac{15}{9}, \frac{- 3}{9})$
B $(\frac{1}{4}, \frac{15}{4}, \frac{- 3}{4})$
C $(\frac{4}{9}, \frac{11}{3}, \frac{- 10}{9})$
D $(\frac{- 1}{9}, \frac{12}{9}, \frac{1}{9})$

Verified Solution

Answer & Solution

Correct Answer

(C) $(\frac{4}{9}, \frac{11}{3}, \frac{- 10}{9})$

Step-by-step Solution

Detailed explanation

Point E is the centroid of face ABC ( which is a triangle) Centroid =x1+x2+x33,y1+y2+y33,z1+z2+z33 E=2+(-3)+(-1)3,3+3+43,-4+(-2)+23 E=-23,103,-43 Point F is the centroid of face ACD F=2+(-1)+33,3+4+53,-4+2+13 F=43,123,-13=43,4,-13 Point G is the centroid of face ABD…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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A2,3,-4, B-3,3,-2, C-1,4,2 and D3,5,1 are the vertices of a tetrahedron. If E, F, G are the centroids of its faces containing the point A, then the centroid of the triangle EFG is

Step-by-step Solution

$A (2, 3, - 4), B (- 3, 3, - 2), C (- 1, 4, 2)$ and $D (3, 5, 1)$ are the vertices of a tetrahedron. If $E, F, G$ are the centroids of its faces containing the point $A,$ then the centroid of the triangle $E F G$ is