TS EAMCET · Maths · Functions
The maximum value of \(\left\{x \in \mathbf{R} / \sqrt{x+2}>\sqrt{8-x^2}\right\}=\)
- A 2
- B \(\sqrt{2}+1\)
- C 3
- D \(2 \sqrt{2}\)
Answer & Solution
Correct Answer
(D) \(2 \sqrt{2}\)
Step-by-step Solution
Detailed explanation
Given \(\left\{x \in \mathbf{R}: \sqrt{x+2}>\sqrt{8-x^2}\right\}\) \(\therefore\) Defining the function \(x+2 \geq 0 \Rightarrow x \geq-2\) \(\ldots\) (i) and \(8-x^2 \geq 0 \Rightarrow x \in[-2 \sqrt{2}, 2 \sqrt{2}]\) \(\ldots\) (ii) Now, \(\sqrt{x+2}>\sqrt{8-x^2}\)…
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