TS EAMCET · Maths · Three Dimensional Geometry
The image of the point \((2,4)\) with respect to the straight line \(2 x+3 y-6=0\) is
- A \(\left(-\frac{14}{13},-\frac{8}{13}\right)\)
- B \(\left(\frac{14}{13}, \frac{8}{13}\right)\)
- C \(\left(-\frac{2}{13},-\frac{4}{13}\right)\)
- D \(\left(-\frac{2}{7},-\frac{8}{7}\right)\)
Answer & Solution
Correct Answer
(A) \(\left(-\frac{14}{13},-\frac{8}{13}\right)\)
Step-by-step Solution
Detailed explanation
Let the image of the point \(A(2,4)\) in the line mirror \(D E\) be \(C(\alpha, \beta)\). Then, \(A C\) is perpendicular to \(D E\). \(\therefore\) The coordinate of point \(B\) are \(\left(\frac{\alpha+2}{2}, \frac{\beta+4}{2}\right)\). Since, point \(B\) lies on the line…
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