TS EAMCET · Maths · Differential Equations
The general solution of the differential equation \(\frac{d y}{d x}=\frac{2 y^2+1}{2 y^3-4 x y+y}\) is
- A \(4 x y^2+2 x=y^4+y^2+c\)
- B \(2 x y^2+x=y^4-y^2+c\)
- C \(4 x y^2-2 x=y^4+y^2+c\)
- D \(4 x y^2+2 x=y^4-y^2+c\)
Answer & Solution
Correct Answer
(A) \(4 x y^2+2 x=y^4+y^2+c\)
Step-by-step Solution
Detailed explanation
\(\frac{d x}{d y}=\frac{2 y^3+y-4 x y}{2 y^2+1}=y-\frac{4 x y}{2 y^2+1}\)…
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