TS EAMCET · Maths · Parabola
The equation of the tangent to the curve \(x^2+y-7=4 x\) at the point \((1,10)\) is
- A y = 2x + 8
- B y = x + 8
- C y = –2x – 14
- D y = x – 4
Answer & Solution
Correct Answer
(A) y = 2x + 8
Step-by-step Solution
Detailed explanation
Given curve is \(x^2+y-7=4 x\) now tangent at \((1,10)\) is \(\begin{aligned} & 1 \mathrm{x}+\left(\frac{\mathrm{y}+10}{2}\right)-7-4\left(\frac{\mathrm{x}+1}{2}\right)=0 \\ & \Rightarrow \mathrm{y}=2 \mathrm{x}+8 \end{aligned}\)
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