TS EAMCET · Maths · Circle
The equation of a circle concentric with the circle \(x^2+y^2-6 x+12 y+15=0\) and having area that is twice the area of the given circle is
- A \(x^2+y^2-6 x+12 y-15=0\)
- B \(x^2+y^2-6 x+12 y-30=0\)
- C \(x^2+y^2-6 x+12 y-60=0\)
- D \(x^2+y^2-6 x+12 y+15=0\)
Answer & Solution
Correct Answer
(A) \(x^2+y^2-6 x+12 y-15=0\)
Step-by-step Solution
Detailed explanation
Given, \[ x^2+y^2-6 x+12 y+15=0 \] Centre (3,-6) \[ r=\sqrt{9+36-15}=\sqrt{30} \] Area \(\quad=\pi(\sqrt{30})^2=30 \pi\) Required equation of circle has twice the area of circle…
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