TS EAMCET · Maths · Ellipse
The eccentricity of an ellipse passing through \((3 \sqrt{2}, \sqrt{10})\) with foci at \((-4,0)\) and \((4,0)\) is
- A \(\frac{1}{2}\)
- B \(\frac{2}{3}\)
- C \(\frac{\sqrt{2}}{3}\)
- D \(\frac{1}{\sqrt{3}}\)
Answer & Solution
Correct Answer
(B) \(\frac{2}{3}\)
Step-by-step Solution
Detailed explanation
Let the equation of ellipse be, \(\frac{x^2}{a^2}+\frac{y^2}{b^2}=1\) It passes through \((3 \sqrt{2}, \sqrt{10})\) \(\therefore \quad \frac{18}{a^2}+\frac{10}{b^2}=1\) ...(i) Also, foci are \(( \pm 4,0)\)…
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