TS EAMCET · Maths · Straight Lines
The distance between the point \((2,1)\) and the image of the point \((3,-1)\) with respect to the line \(2 x+y-1=0\) is
- A \(\sqrt{\frac{37}{5}}\)
- B \(\sqrt{\frac{81}{5}}\)
- C \(\sqrt{\frac{89}{5}}\)
- D \(\sqrt{\frac{29}{5}}\)
Answer & Solution
Correct Answer
(C) \(\sqrt{\frac{89}{5}}\)
Step-by-step Solution
Detailed explanation
Image of point \((3,-1)\) with respect to line \(\begin{aligned} & 2 x+y-1=0 \text { is } \\ & \frac{x-3}{2}=\frac{y+1}{1}=-2 \frac{(6-1-1)}{5}=\frac{-8}{5} \\ & x=\frac{-16}{5}+3=\frac{-1}{5} \Rightarrow y=\frac{-8}{5}-1=\frac{-13}{5} \end{aligned}\) Image…
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