TS EAMCET · Maths · Differential Equations
The differential equation for which \(y^2=4 a(x+a)\) (where \(a\) is a parameter) is general solution, is
- A \(y-y y^{\prime 2}=2 x y^{\prime}\)
- B \(y+y y^{\prime 2}=2 x y^{\prime}\)
- C \(y\left(y+y^{\prime}\right)=2 x y^{\prime}\)
- D \(y\left(y-y^{\prime}\right)=2 x y^{\prime}\)
Answer & Solution
Correct Answer
(A) \(y-y y^{\prime 2}=2 x y^{\prime}\)
Step-by-step Solution
Detailed explanation
Given, \(y^2=4 a(x+a)\) ...(i) On differentiation, \(2 y \frac{d y}{d x}=4 a(1+0)=4 a\) \(a=\frac{1}{2} y y^{\prime}\) [put in Eq. (i)]…
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