TS EAMCET · Maths · Pair of Lines
The combined equation of the pair of straight lines passing through the point of intersection of the pair of lines \(x^2+4 x y+3 y^2-4 x-10 y+3=0\) and having slopes \(\frac{1}{2}\) and \(-\frac{1}{3}\) is
- A \(x^2-y^2-8 x-2 y+15=0\)
- B \(x^2+7 x y+12 y^2-x-4 y=0\)
- C \(x^2+7 x y+10 y^2-x-8 y-2=0\)
- D \(x^2+x y-6 y^2-7 x-16 y+6=0\)
Answer & Solution
Correct Answer
(D) \(x^2+x y-6 y^2-7 x-16 y+6=0\)
Step-by-step Solution
Detailed explanation
Combined equation of the pair of straight line \(x^2+4 x y+3 y^2-4 x-10 y+3=0\) is in the form of \(a x^2+2 h x y+b y^2+2 g x+2 f y+c=0\) \[ \therefore a=1,2 h=4 \Rightarrow h=2, b=3, g=-2, f=-5, c=3 \] So, point of intersection of pair of straight line is…
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