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TS EAMCET · Maths · Quadratic Equation

If \(2+\sqrt{3}\) is a root of the equation \(f(x)=x^4+2 x^3-16 x^2-22 x+7=0\), then which one of the following is not a root of \(f(x)=0 ?\)

  1. A \(3-\sqrt{2}\)
  2. B \(2-\sqrt{3}\)
  3. C \(-3+\sqrt{2}\)
  4. D \(-3-\sqrt{2}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(3-\sqrt{2}\)

Step-by-step Solution

Detailed explanation

\(2+\sqrt{3}\) is a root of \(x^4+2 x^3-16 x^2-22 x+7=0\) \(\therefore 2-\sqrt{3}\) is also a root of \(\begin{aligned} x^4+2 x^3-16 x^2-22 x+7 & =0 \\ \because \quad x=2+\sqrt{3} & \\ (x-2)^2 & =(\sqrt{3})^2 \Rightarrow x^2-4 x+4-3=0 \\ x^2-4 x+1 & =0 \end{aligned}\)When…