TS EAMCET · Maths · Binomial Theorem
The binomial expansion \((7+3 x)^{-2 / 5}\) is valid for all \(x\) in the interval \(\left(\frac{-7}{3}, \frac{7}{3}\right)\) and if the 4 th term of its expansion is \(k x^3\), then \(\left(7^{12 / 5} k\right)=\)
- A \(\frac{-2}{125}\)
- B \(\frac{-108}{125}\)
- C \(\frac{-72}{125}\)
- D \(-\frac{36}{125}\)
Answer & Solution
Correct Answer
(B) \(\frac{-108}{125}\)
Step-by-step Solution
Detailed explanation
We have, \((7+3 x)^{-2 / 5}=7^{-2 / 5}\left(1+\frac{3}{7} x\right)^{-2 / 5}\) 4th term of expansion is…
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