TS EAMCET · Chemistry · Structure of Atom
The electronic configuration of \({ }_{59} \mathrm{Pr}\) (praseodimium) is
- A \(\left[{ }_{54} \mathrm{Xe}\right] 4 f^2 5 d^1 6 s^2\)
- B \(\left[{ }_{54} \mathrm{Xe}\right] 4 f^1 5 d^2 6 s^2\)
- C \(\left[{ }_{54} \mathrm{Xe}\right] 4 f^3 6 s^2\)
- D \(\left.{ }_{54} \mathrm{Xe}\right] 4 f^3 5 d^2\)
Answer & Solution
Correct Answer
(C) \(\left[{ }_{54} \mathrm{Xe}\right] 4 f^3 6 s^2\)
Step-by-step Solution
Detailed explanation
Electronic configuration of \({ }_{59} \mathrm{Pr}\) (praseodimium). [Xe] \(4 f^3 5 d^{\circ} 6 s^2\)
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