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TS EAMCET · Maths · Area Under Curves

The area (in sq units) bounded by the curves \(y^2=4 x\) and \(x^2=4 y\) is

  1. A \(\frac{64}{3}\)
  2. B \(\frac{16}{3}\)
  3. C \(\frac{8}{3}\)
  4. D \(\frac{2}{3}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{16}{3}\)

Step-by-step Solution

Detailed explanation

Given curves are \(y^2=4 x\) and \(x^2=4 y\). The intersection point is \(x^4=16 y^2=16(4 x)\) \(\begin{array}{rlrl}\Rightarrow & x\left(x^3-64\right) & =0 \\ \Rightarrow & & x & =0,4 \\ \Rightarrow & & y & =0,4\end{array}\) Hence, intersection point is \(O(0,0)\) and \(A(4,4)\)…
From TS EAMCET
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