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TS EAMCET · Maths · Vector Algebra

The angle between the vectors 2k^-3j^ and i^-2k^ is

  1. A cos-1865
  2. B cos-1-465
  3. C cos-1265
  4. D cos-1313
Verified Solution

Answer & Solution

Correct Answer

(B) cos-1-465

Step-by-step Solution

Detailed explanation

Given Vectors are 2k^-3j^   &  i^-2k^ Now, For a→ & b→ their dot product is a→.b→=a→b→cosθ ⇒cosθ=a→.b→a→b→ ∴cosθ=2k^-3j^.i^-2k^2k^-3j^i^-2k^…