TS EAMCET · Maths · Application of Derivatives
The angle between the curves \(y=\sin 2 x\) and \(y=\cos 2 x\) is
- A \(\tan ^{-1} \sqrt{2}\)
- B \(\tan ^{-1} 2 \sqrt{2}\)
- C \(\tan ^{-1}\left(\frac{1}{\sqrt{2}}\right)\)
- D \(\tan ^{-1}\left(\frac{1}{2 \sqrt{2}}\right)\)
Answer & Solution
Correct Answer
(B) \(\tan ^{-1} 2 \sqrt{2}\)
Step-by-step Solution
Detailed explanation
Given equation of curves are \[ \begin{aligned} & y=\sin 2 x \\ & y=\cos 2 x \end{aligned} \] and Let us first find the point of intersection, for this consider.…
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