TS EAMCET · Maths · Circle
The angle between the circles \(x^2+y^2-2 x-9=0\) and \(x^2+y^2-4 y-1=0\) at their point of intersection is
- A \(\frac{\pi}{6}\)
- B \(\frac{\pi}{4}\)
- C \(\frac{\pi}{3}\)
- D \(\frac{\pi}{2}\)
Answer & Solution
Correct Answer
(B) \(\frac{\pi}{4}\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { (b) Let } C_1=\text { centre of first circle }=(1,0) \\ & C_2=\text { centre of second circle }=(0,2) \\ & r_1=\text { radius of first circle }=\sqrt{1+0+9}=\sqrt{10} \\ & r_2=\text { radius of second circle }=\sqrt{0+4+1}=\sqrt{5} \\ & d=C_1…
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