TS EAMCET · Maths · Permutation Combination
Number of all possible words (with or without meaning) that can be formed using all the letters of the word CABINET in which neither the word CAB nor the word NET appear is
- A \(5040\)
- B \(4806\)
- C \(4800\)
- D \(5034\)
Answer & Solution
Correct Answer
(B) \(4806\)
Step-by-step Solution
Detailed explanation
Total permutations of CABINET: \(7! = 5040\) Permutations with "CAB": Treat CAB as a block. \((\text{CAB}), \text{I}, \text{N}, \text{E}, \text{T}\) is 5 items. \(5! = 120\) Permutations with "NET": Treat NET as a block. \((\text{NET}), \text{C}, \text{A}, \text{B}, \text{I}\)…
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