TS EAMCET · Maths · Parabola
Let \(x+y=k\) be a normal to the parabola \(y^2=12 x\). If \(p\) is length of the perpendicular from the focus of the parabola onto this normal, then \(4 k-2 p^2\) is equal to
- A \(1\)
- B \(0\)
- C \(-1\)
- D \(2\)
Answer & Solution
Correct Answer
(B) \(0\)
Step-by-step Solution
Detailed explanation
Given equation of parabola is \(y^2=12 x\) Here, \(\quad a=3\) \(\therefore\) Equation of normal is \(\begin{aligned} y & =m x-2 a m-a m^3 \quad(\because m=-1) \\ y & =-x-2(3)(-1)-3(-1)^3 \\ & =-x+6+3\end{aligned}\) But given normal is…
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