TS EAMCET · Maths · Properties of Triangles
In \(\triangle A B C,(a+b+c)\left(\tan \frac{A}{2}+\tan \frac{B}{2}\right)\) is equal to
- A \(2 c \cot \frac{C}{2}\)
- B \(2 a \cot \frac{A}{2}\)
- C \(2 b \cot \frac{\bar{B}}{2}\)
- D \(\tan \frac{C}{2}\)
Answer & Solution
Correct Answer
(A) \(2 c \cot \frac{C}{2}\)
Step-by-step Solution
Detailed explanation
We have, \((a+b+c)\left(\tan \frac{A}{2}+\tan \frac{B}{2}\right)\)…
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