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TS EAMCET · Maths · Complex Number

Let \(A_r=\left(x+\frac{1}{x}\right)^3 \cdot\left(x^2+\frac{1}{x^2}\right)^3 \cdot\left(x^3+\frac{1}{x^3}\right)^3 \ldots\). \(\left(x^r+\frac{1}{x^r}\right)^3\). If \(x^2+x+1=0\), then \(\frac{1}{A_3}+\frac{1}{A_6}+\frac{1}{A_9}+\frac{1}{A_{12}}+\ldots . . \infty=\)

  1. A \(\frac{1}{6}\)
  2. B \(\frac{2}{5}\)
  3. C 1
  4. D \(\frac{1}{7}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\frac{1}{7}\)

Step-by-step Solution

Detailed explanation

It is given that, if \(x^2+x+1=0\), then \(A_r=\left(x+\frac{1}{x}\right)^3\left(x^2+\frac{1}{x^2}\right)^3\left(x^3+\frac{1}{x^3}\right)^3 \ldots\left(x^r+\frac{1}{x^r}\right)^3\) As, we know that \(w\) and \(w^2\) are roots of quadratic equation \(x^2+x+1=0\), so \(w^3=1\) and…