TS EAMCET · Maths · Complex Number
Let \(A_r=\left(x+\frac{1}{x}\right)^3 \cdot\left(x^2+\frac{1}{x^2}\right)^3 \cdot\left(x^3+\frac{1}{x^3}\right)^3 \ldots\). \(\left(x^r+\frac{1}{x^r}\right)^3\). If \(x^2+x+1=0\), then \(\frac{1}{A_3}+\frac{1}{A_6}+\frac{1}{A_9}+\frac{1}{A_{12}}+\ldots . . \infty=\)
- A \(\frac{1}{6}\)
- B \(\frac{2}{5}\)
- C 1
- D \(\frac{1}{7}\)
Answer & Solution
Correct Answer
(D) \(\frac{1}{7}\)
Step-by-step Solution
Detailed explanation
It is given that, if \(x^2+x+1=0\), then \(A_r=\left(x+\frac{1}{x}\right)^3\left(x^2+\frac{1}{x^2}\right)^3\left(x^3+\frac{1}{x^3}\right)^3 \ldots\left(x^r+\frac{1}{x^r}\right)^3\) As, we know that \(w\) and \(w^2\) are roots of quadratic equation \(x^2+x+1=0\), so \(w^3=1\) and…
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